系统工程与电子技术 ›› 2023, Vol. 45 ›› Issue (5): 1420-1428.doi: 10.12305/j.issn.1001-506X.2023.05.18
• 系统工程 • 上一篇
王俊龙1, 楼京俊1,*, 阮旻智1, 李华2
收稿日期:
2021-12-23
出版日期:
2023-04-21
发布日期:
2023-04-28
通讯作者:
楼京俊
作者简介:
王俊龙 (1985—), 男, 讲师, 博士研究生, 主要研究方向为装备维修保障Junlong WANG1, Jingjun LOU1,*, Minzhi RUAN1, Hua LI2
Received:
2021-12-23
Online:
2023-04-21
Published:
2023-04-28
Contact:
Jingjun LOU
摘要:
针对舰船装备远航任务时间长、远离岸基且备件难以及时得到补给的现实, 系统研究了面向任务的舰船装备备件利用率计算问题。首先, 对单元级备件利用率的计算方法进行了分析, 建立了单元级备件利用率模型。其次, 基于上述基础, 按照备件短缺时是否会引起系统停止工作的标准, 把备件分为关键单元(会引起系统停机)和非关键单元(不会引起系统停机), 将复杂装备系统近似为串联系统, 按照任务成功或失败两种情况研究了任务过程中系统级备件利用率计算模型。然后,以任务成功率为指标约束, 建立了远航任务装备系统级备件利用率的计算模型。案例计算与仿真分析表明, 所提模型能够满足工程应用要求, 可为装备保障部门制定远航任务备件配置方案提供理论支撑。
中图分类号:
王俊龙, 楼京俊, 阮旻智, 李华. 面向任务的舰船装备备件利用率计算模型[J]. 系统工程与电子技术, 2023, 45(5): 1420-1428.
Junlong WANG, Jingjun LOU, Minzhi RUAN, Hua LI. Mission-oriented calculation model of warship equipment spare parts utilization rate[J]. Systems Engineering and Electronics, 2023, 45(5): 1420-1428.
表1
单元的备件利用率结果"
任务时间/h | 指数分布 EXP(0.002) | 伽马分布 Ga(1.3, 0.002) | 正态分布 N(500, 1702) | |||||
仿真结果 | 解析结果 | 仿真结果 | 解析结果 | 仿真结果 | 解析结果 | |||
600 | 0.395 | 0.386 | 0.266 | 0.270 | 0.252 | 0.257 | ||
700 | 0.423 | 0.443 | 0.311 | 0.318 | 0.323 | 0.330 | ||
800 | 0.493 | 0.497 | 0.360 | 0.366 | 0.389 | 0.391 | ||
900 | 0.542 | 0.547 | 0.409 | 0.412 | 0.446 | 0.450 | ||
1 000 | 0.602 | 0.594 | 0.447 | 0.457 | 0.513 | 0.514 | ||
1 100 | 0.623 | 0.637 | 0.505 | 0.501 | 0.570 | 0.583 | ||
1 200 | 0.670 | 0.677 | 0.531 | 0.542 | 0.648 | 0.650 | ||
1 300 | 0.719 | 0.713 | 0.573 | 0.581 | 0.716 | 0.714 | ||
1 400 | 0.740 | 0.746 | 0.615 | 0.619 | 0.769 | 0.773 | ||
1 500 | 0.794 | 0.776 | 0.660 | 0.653 | 0.816 | 0.827 | ||
1 600 | 0.805 | 0.803 | 0.682 | 0.686 | 0.876 | 0.876 | ||
1 700 | 0.827 | 0.827 | 0.734 | 0.716 | 0.915 | 0.917 | ||
1 800 | 0.855 | 0.848 | 0.733 | 0.745 | 0.953 | 0.948 | ||
1 900 | 0.870 | 0.867 | 0.770 | 0.770 | 0.969 | 0.971 | ||
2 000 | 0.886 | 0.884 | 0.770 | 0.794 | 0.984 | 0.985 | ||
2 100 | 0.901 | 0.899 | 0.814 | 0.816 | 0.994 | 0.993 | ||
2 200 | 0.908 | 0.912 | 0.843 | 0.836 | 0.998 | 0.997 | ||
2 300 | 0.916 | 0.924 | 0.860 | 0.854 | 0.999 | 0.999 | ||
2 400 | 0.941 | 0.934 | 0.873 | 0.870 | 0.999 | 1.000 | ||
2 500 | 0.947 | 0.943 | 0.895 | 0.885 | 1.000 | 1.000 | ||
2 600 | 0.947 | 0.950 | 0.894 | 0.898 | 1.000 | 1.000 | ||
2 700 | 0.957 | 0.957 | 0.899 | 0.910 | 1.000 | 1.000 | ||
2 800 | 0.967 | 0.963 | 0.928 | 0.921 | 1.000 | 1.000 | ||
2 900 | 0.971 | 0.968 | 0.929 | 0.930 | 1.000 | 1.000 | ||
3 000 | 0.967 | 0.973 | 0.940 | 0.939 | 1.000 | 1.000 |
表4
各备件方案的保障效果计算结果"
序号 | 备件方案(各单元的备件数量) | 任务成功率Ps | 备件利用率Pb | ||||||||
单元1 | 单元2 | 单元3 | 单元4 | 单元5 | 仿真结果 | 解析结果 | 仿真结果 | 解析结果 | |||
1 | 1 | 1 | 1 | 3 | 2 | 0.002 | 0.001 | 0.375 | 0.375 | ||
2 | 1 | 1 | 2 | 3 | 2 | 0.035 | 0.033 | 0.389 | 0.386 | ||
3 | 2 | 1 | 2 | 3 | 2 | 0.060 | 0.070 | 0.473 | 0.476 | ||
4 | 2 | 2 | 2 | 3 | 2 | 0.136 | 0.133 | 0.556 | 0.543 | ||
5 | 3 | 2 | 2 | 3 | 2 | 0.213 | 0.203 | 0.584 | 0.582 | ||
6 | 3 | 2 | 3 | 3 | 2 | 0.397 | 0.377 | 0.579 | 0.576 | ||
7 | 3 | 3 | 3 | 3 | 2 | 0.501 | 0.506 | 0.592 | 0.591 | ||
8 | 4 | 3 | 3 | 3 | 2 | 0.643 | 0.637 | 0.610 | 0.601 | ||
9 | 5 | 3 | 3 | 3 | 2 | 0.704 | 0.716 | 0.581 | 0.585 | ||
10 | 5 | 4 | 3 | 3 | 2 | 0.807 | 0.805 | 0.571 | 0.572 | ||
11 | 6 | 4 | 3 | 3 | 2 | 0.860 | 0.850 | 0.548 | 0.549 | ||
12 | 6 | 4 | 4 | 3 | 2 | 0.913 | 0.911 | 0.521 | 0.526 |
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